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大神进 json 数组怎么写

你那个数组是有问题的,要 var c = '[{"name":"张三","age":18},{"name":"李四","age":19}]'; 这样定义

使用JSON最简单的方法是使用第三方序列化类库,如JSON.NET。

menuvar json = [ { "index": "name", "id": 4, "colspan": 1, "sort": 0, "title": "你是", "age": 40 }, { "id": 4, "colspan": 3, "sort": 1, "title": "我", "age": 40 }, { "id": 4, "colspan": 15, "sort": 2, "title": "的", "age": 40 }...

import java.util.HashMap; import java.util.Map; import com.alibaba.fastjson.JSONArray; import com.alibaba.fastjson.JSONObject; public class JsonArray { public static void main(String[] args) { //建立两个数组,分别是ja和jb JSONA...

我也看烦了,看着似乎有点明白,但又不怎么明白,先把代码写出来,再说说你这个json 代码如下: $.each(h, function () {//h就是你的json了 var h1 = this; alert("a:" + h1.a); $.each(h1.a1, function () { var h2 = this; alert("a2:" + h2.a...

success:function(data){ var html=''; var dataObj=data.dataObject; $.each(dataObj,function(i,obj){ if(i%2==0)html+=''; html+=''+obj.iconUrl+''; if(i%2==1)html+=''; } if(dataObj.length%2!=0)html+=''; alert(html);},

var c = a.concat(b),//合并成一个数组temp = {},//用于id判断重复result = [];//最后的新数组//遍历c数组,将每个item.id在temp中是否存在值做判断,如不存在则对应的item赋值给新数组,并将temp中item.id对应的key赋值,下次对相同值做判断时...

var json1=[{"age":5,"num":2,"people":3,"class":9},{"age":1,"num":3,"people":2,"class":8},{"age":4,"num":6,"people":5,"class":3}]; var json2=[{"field":"age","typle":"sum","title":"ss"},{"field":"num","typle":"sum","title":"ss"}...

大概写了个,应该可以满足你的要求: json = [ {"time": "1122", "a": "123", "b": "234"}, {"time": "1133", "a": "456", "b": "567"}]var arr = [];for(var i=0;i

你很懒。 第一步,封装json. var jsonStr = [{'name':'jim' , 'age':20} , {'name':'king' , 'age':26},{'name':'jge' , 'age':30}] 第二部,ajax。 jQuery.ajax({ type: "post", url: url, dataType : 'json', data : {'mydata':jsonStr}, succ...

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